450-18x^2=0

Solution for 450-18x^2=0 equation:

450-18x^2=0

a = -18; b = 0; c = +450;
Δ = b2-4ac
Δ = 02-4·(-18)·450
Δ = 32400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{32400}=180$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-180}{2*-18}=\frac{-180}{-36}
=+5
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+180}{2*-18}=\frac{180}{-36}
=-5
$